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2v^2-9v-56=0
a = 2; b = -9; c = -56;
Δ = b2-4ac
Δ = -92-4·2·(-56)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-23}{2*2}=\frac{-14}{4} =-3+1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+23}{2*2}=\frac{32}{4} =8 $
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